C语言之切割字符串

[i=s] 本帖最后由 Ject 于 2023-9-1 23:20 编辑 [/i]<br /> <br /> #### 如题：将字符串进行切割，输入const char * ，分隔符为[，]，数据示例[234,211,222] ```c #include <stdio.h> #include <stdlib.h> #include <string.h> void parse_input(const char *input, int *a, int *b, int *c) { char *input_copy = strdup(input); char *token = strtok(input_copy, ","); *a = atoi(token); token = strtok(NULL, ","); *b = atoi(token); token = strtok(NULL, ","); *c = atoi(token); free(input_copy); } int main() { const char *input = "255,254,250"; int a, b, c; parse_input(input, &a, &b, &c); printf("a: %d\n", a); printf("b: %d\n", b); printf("c: %d\n", c); return 0; } ``` 办法千千万，欢迎大家用别的办法回帖。

[i=s] 本帖最后由 Ject 于 2023-9-1 23:28 编辑 [/i]<br /> <br /> #### 方法二 ```c #include <stdio.h> void parse_input(const char *input, int *a, int *b, int *c) { sscanf(input, "%d,%d,%d", a, b, c); } int main() { const char *input = "255,254,250"; int a, b, c; parse_input(input, &a, &b, &c); printf("a: %d\n", a); printf("b: %d\n", b); printf("c: %d\n", c); return 0; } ``` 使用c语言标准输入，未经验证，欢迎验证

#### 方法三 ```c #include stdlib.h void parse_input(const char *input, int *a, int *b, int *c) { char *end; *a = strtol(input, &end, 10); *b = strtol(end + 1, &end, 10); *c = strtol(end + 1, &end, 10); } int main() { const char *input = "255,254,250"; int a, b, c; parse_input(input, &a, &b, &c); printf("a: %d\n", a); printf("b: %d\n", b); printf("c: %d\n", c); return 0; } ```

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